1.

State roults law for a sodium containing non voletile solute desolve in voletile solvent​

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Answer:

The vapour pressure of a solution of a non-volatile solute is EQUAL to the vapour pressure of the pure solvent at that temperature multiplied by its MOLE FRACTION.

In equation form:

pT=pB0.χB

In this equation, pB0 is the vapour pressure of the pure solvent at a particular temperature, pT is the total pressure of the solution, χB is the mole fraction of the solvent.

For a solution of a volatile solute (A) and solvent (B) total pressure is sum of the partial pressure of the TWO as:

pT=pA0.χA+pB0.χB

As χA++χB=1 or χA=1−χB

or pT=pA0.(1−χB)+pB0.χB

pT=pA0+(pB0−pA0).χB

For non-volatile solute pA0=0

thus pT=pB0.χB

Limitations of Raoult's law:

1. Intermolecular forces between the solvent and solute components shoul be similar to those betweenindividual molecules

A_A=B-B=A-B

2. The GASEOUS phase are assumed to behave ideal where ideal gas law can be applied.


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