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State the explain the law of conservation of momentum of the system of particle.

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p>Solution :Newton.s second law for the system of particle, `(dvecp)/(dt)=vecF_(<a href="https://interviewquestions.tuteehub.com/tag/ext-447179" style="font-weight:bold;" target="_blank" title="Click to know more about EXT">EXT</a>)` <br/> If the sum of external forces acting on the system of particles is zero then <br/> `(dvecp)/(dt)=0` <br/> `therefore dvecp=0, therefore vec(p_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))=vecp_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> Means the linear momentum remains constant. (`vecp` = constant) <br/> Equation `vecp` = constant, it is equivalent to three scalar equation as following : <br/> `p_(x)=C_(1),p_(y)=C_(2),p_(3)=C_(3)` <br/> where `p_(x),p_(y),andp_(z)` are the components of linear momentum `vecp` for respective axis X, Y and Z-axis and `C_(1),C_(2)andC_(3)` are constant. <br/> ..When external total force acting on a system of particles is zero, then its total linear momentum remains constant... This is known as conservation of linear momentum. <br/> From `MvecA=vecF`, here `vecF` is total external force. <br/> If `vecF=0` then `MvecA=0` <br/> `therefore <a href="https://interviewquestions.tuteehub.com/tag/veca-3257210" style="font-weight:bold;" target="_blank" title="Click to know more about VECA">VECA</a>=0` <br/> Means, ..when total external force on system is zero, the velocity of centre of mass remains constant... <br/> More over `vecA=(dvecv)/(dt)` then <br/> If `vecA=0` then `(dvecv)/(dt)=0` <br/> `therefore vecv` is constant. <br/> Means, total external force on the system is zero, the velocity of centre of mass remains constant.</body></html>


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