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Statement : Passes of charge through `CuSO_(4)(aq)` solution in presence of `Pt` electode increase it `pH`. Explanation : Concentration of `[OH^(-)]` in solution decreases.A. `S` is correct but `E` is wrongB. `S` is wrong but `E` is correct.C. Both `S` and `E` are correct and `E` is correct explanation of `S`.D. Both `S` and `E` are correct but `E` is not correct explanation of `S`. |
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Answer» Correct Answer - C Anode: `2H^(2)O rarr 4H^(+) + O_(2) + 4e` or `2OH^(-) rarr H_(2)O + (1)/(2)O_(2) + 2e` Cathode: `Cu^(2+) + 2e rarr Cu`. |
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