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Suppose the charge of a proton and an electron differ slightely. One of them is `-e`, the other is `(e+Deltae)`. If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance `d` (much greater than atomic size) apart is zero. Then `Deltae` is of the order of [Given mass of hydrogen `m_(h)=1.67xx10^(-27)kg`]A. `10^(-20) C`B. `10^(-23) C`C. `10^(-37) C`D. `10^(-47) C` |
Answer» Correct Answer - C Here, electrostiac force = gravitonal force `(k(e + Delta e)^(2))/(d^(2)) = (G m_(h) m_(h))/(d^(2))` `(e + Delta e)^(2) = (G m_(h) m_(h))/(k)` `= (6.7xx10^(-11)(1.67xx10^(-27))^(2))/(9xx10^(9))` `(6.7xx1.67xx1.67)/(9) xx10^(-74)` `e + Delta e = (2.076xx10^(-74))^(1//2) = 1.44xx10^(-37)` Hence `Delta e` is of the order of `10^(-37) C` |
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