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| 1. |
T.V. transmission tower at a particular station has a height of `160m`. (`a`) What is the coverage range? (`b`) How much population is covered by transmission, if the average population density around the tower is `1200 per km^(2)`? (`c`) What should be the height of tower to double the coverage range |
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Answer» (`a`) Coverage range `d=sqrt(2Rh)` `=sqrt(2xx6400xx10^(3)xx160m)` `=45.254 km` (`b`) Population covered `=("population density")xx("area covered")` `=(1200)xx(pi d^(2))` `=(2400piRh)=2400xx3.14xx6.4xx10^(3)xx0.16` `=77.17lac` (`c`) Coverage range `propsqrt(h)` Therefore coverage range can be doubled by making height of the lower four times to `640m`. So, height of the lower should be increased by `480 m`. |
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