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InterviewSolution
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Temperature of two moles of a monoatomic gas is increased by `300 K` in the process `p prop V`. Find (a) molar heat capacity of the gas in the given process (b) heat required in the given process. |
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Answer» Correct Answer - A::B::C (a) Molar heat capacity `C` is given by `C = C_V + R/ (1 - x)` in the process `p V^(x) =` constant . Now, `C_V = 3/2 R` for monoatomic gas. Further, the given process can be written as `PV^-1 = constant` `:. x = -1` Substituting the values in Eq. (i), we have `C = 3/2 R + R(1 + 1) = 2 R` (b) `Q or DeltaQ = n C Delta T` Substituting the values, we have `Delta Q = (2) (2R) (300)` = `1200 R`. |
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