The acceleration of a particle in ms^(-1) is given by a=3t^(2)+2t+2 where timer is in second If the particle starts with a velocity v=2ms^(-1) at t=0 then find the velocity at the end of 2s.

The acceleration of a particle in ms^(-1) is given by a=3t^(2)+2t+2 wh

1.	The acceleration of a particle in ms^(-1) is given by a=3t^(2)+2t+2 where timer is in second If the particle starts with a velocity v=2ms^(-1) at t=0 then find the velocity at the end of 2s.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`a=(dv)/(dt)=(<a href="https://interviewquestions.tuteehub.com/tag/3t-311358" style="font-weight:bold;" target="_blank" title="Click to know more about 3T">3T</a>^(2)+2t+2)dt` <br/> `dv=(3t+2t+2)dt` <br/> `intdv=int(3t^(2)+2t+2)dt` <br/> `v=t^(3)+t^(2)+2t+C` <br/> `c=2m//s,v=18m//s` at t=2s</body></html>