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InterviewSolution
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The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound isA. acetamideB. benzamideC. ureaD. thiourea |
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Answer» Correct Answer - C Le the vol. of acid left unused = v mL of 0.1 `M H_(2)SO_(4)` Applying molarity equation `n_(a)M_(a)V_(a) = n_(b)M_(b)V_(b)`, we have, `2 xx 0.1 xx v = 1 xx 0.5 xx 20` or v = 50 mL `:.` Vol. of acid used = 100 - 50 = 50 mL of `0.1 M H_(2)SO_(4)` `%N = (1.4 xx n_(1)M_(a)V_(a))/("wt. of substance taken") = (1.4 xx 2 xx 0.1 xx 50)/(0.3)` `= 46.6` % N in urea `(NH_(2)CONH_(2)) = (28//60) xx 100 = 46.6%`, in acetamide `(CH_(3)CONH_(2)) = (14//59) xx 100 = 23.72%`, in benzamide `(C_(6)H_(5)CONH_(2)) = (14//21) xx 100 = 11.57%` and in thiourea `(NH_(2)CSNH_(2)) = (28//76) xx 100 = 36.84%` Thus, option (c) is correct. |
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