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. The average of 1, 3,5,7,9, 11,25 terms is(a) 625(c) 125(b) 25(d) 50 |
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Answer» The number of terms is N =(25-1)/2 + 1= 13The sum of terms, which is the arithmetic progression with difference 2, is:S =(1 + 25) ×13÷ 2 = 13× 13The average is:A = S / N =13× 13 / 13 = 13 So, to calculate the average of arithmetic progressionwas needed to calculate the number of terms N, the average arithmetic progression is the average of first and last term:A = (1 + 25) / 2 = 13 no answer answer 25 |
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