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The bob of simple pendulum is held in the horizantal position calculate the speed of the bob of pendulum at the lowest position B when released and the length of pendulum is 0.5 meter and assume that there is no loss of energy ​

Answer» <html><body><p>Increase in potential Energy of <a href="https://interviewquestions.tuteehub.com/tag/bob-399946" style="font-weight:bold;" target="_blank" title="Click to know more about BOB">BOB</a> =mgΔh where m is mass of bob, g=9.81 ms−2 is acceleration due to gravity and Δh is change in height of bob.As shown in the <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a>, Δh=L−Lcosθ . <a href="https://interviewquestions.tuteehub.com/tag/inserting-1045840" style="font-weight:bold;" target="_blank" title="Click to know more about INSERTING">INSERTING</a> given <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> we getWork <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> on the bob =0.5×9.81(20−20 cos30∘) ⇒ Work done on the bob =0.5×9.81×20(1−√32)=13.1 J</p></body></html>


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