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The chemical compounds are represented by both Empirical and Molecular formulae. Whereas the former is only theoritical, the latter is the actual formula of a compound. In some cases, the two may be even same. A very popular organic compound is a major constituent of alcoholic drinks. (i) What is the empirical of the compound ? (ii) What is its molecular formula ? (iii) Give the chemical name of the compound (iv) Find the percentage composition of the compound ? |
Answer» (i) The empirical formula is `C_(2)H_(6)O` (ii) The molecular formula is also the same i.e., `C_(2)H_(6)O or C_(2)H_(5)OH` (iii) The compound is known as ethanol or ethyl alcohol (iv) Molecular mass of `C_(2)H_(5)OH=2xx` Atomic mass of C + Atomic mass of `O + 6 xx` Atomic mass of H `= 2xx12+16 +6 xx1=46` u Percentage of carbon `(C)=("Mass of C")/("Molecular mass of "C_(2)H_(5)OH)xx100=((24u))/((46u))xx100=52.2` Percentage of oxygen `(O)=("Mass of O")/("Molecular mass of "C_(2)H_(5)OH)xx((16u))/((46u))xx100=34.8` Percentage of hydrogen `(H)=("Mass of H")/("Molecular mass of "C_(2)H_(5)OH)xx100=((6u))/((46u))xx100=13.0`. |
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