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InterviewSolution
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The coagulation of `200 mL` of a positive colloid took place when `0.73 g HCl` was added to it without changing the volume much. The flocculation value of `HCl` for the colloid is a. `36.5` , b. `100` , c. `200` , d. `150`A. `100`B. `36.5`C. `0.365`D. `150` |
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Answer» Correct Answer - A Flocculation value is minimum millimoles of electrolyte to be added to one litre of colloidal solution to cause its coagulation `m_(HCl)= (0.73g)/(36gmol^(-1)) = 0.02mol es` `=0.02xx10^(3)m mol es = 20 m mol es`. `0.2L` of colloidal solution is ppt by `20m` moles. `1L` of colloidal solution is ppt `= (20)/(0.2L) = 100` milli moles. |
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