1.

The coagulation of `200 mL` of a positive colloid took place when `0.73 g HCl` was added to it without changing the volume much. The flocculation value of `HCl` for the colloid is a. `36.5` , b. `100` , c. `200` , d. `150`

Answer» `200mL` of the sol requires `0.73gHCl`
Moles of `HCl=(0.73)/(36.5)mol=0.02mol=20.0mmol`
Therefore, `1000mL(1L)` of the sol will require `=(20)/(200)xx1000=100m mol` `200mL` of the sol requires `0.73gHCl`
Moles of `HCl=(0.73)/(36.5)mol=0.02mol=20.0mmol`
Therefore, `1000mL(1L)` of the sol will require `=(20)/(200)xx1000=100m mol`


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