InterviewSolution
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InterviewSolution
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The coefficient of `x^(n)` in the expansion of `e^(a+bx)` in power of x isA. `(b^(n))/(n!)`B. `e^(a)(b^(n+1))/(n+1)!`C. `e^(a)(b^(n))/(n!)`D. none of these |
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Answer» Answer: We have `e^(a+bx)=e^(a).e^(bx)=e^(a){underset(n=0)overset(infty)Sigma(bx)^(n)/(n!)}` `rarr e^(a+bx)=e^(a){1+(bx)/(1!)+(bx)^(2)/(2!)+(bx)^(3)/(n!)+….}` `therefore` coefficient of `x^(n) in e^(a+bx)=e^(a)(b^(n))/(n!)` |
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