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The compound interest on a certain sum is given by `C.I.=P(1+(R)/(100))^(n)-P`. Find C.I. when `P=rs1000,R=10%` P.a., and n=2. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) `therefore C.I.=rs210` (B) `1000((11)/(10))((11)/(10))-1000=1210-100` (C) Given `Cl=P(1+(R)/(100))^(n)-P,P=rs1000`, R=10% p.a., and n=2 (D) C.I. =`1000+(1+(10)/(100))^(2)-1000`A. BCDAB. DCBAC. CDBAD. BDCA

Answer» Correct Answer - C
C,D,B, and A is the required sequential order


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