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The conductivity of 0.01 mol `L^(-1)`KCl solution is `1.41xx10^(-3)" S "cm^(-1)`. What is the molar conductivity (`S cm^(2) mol^(-1)`) ?A. 14.1B. 1.41C. 1410D. 141 |
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Answer» Correct Answer - D (d) Molar conductivity`(Lambda_(m))=(1000xxk)/(M)` `=(1000xx(1.41xx10^(-3)" S " cm^(-1)))/((0.01" mol "cm^(-3)))=141" S "cm^(-2)mol^(-1)` |
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