The conductivity of 0.02 M AgNO3 at 25°C is 2.428 × 10-3Ω-1cm-1. W

1.	The conductivity of 0.02 M AgNO3 at 25°C is 2.428 × 10-3Ω-1cm-1. What is its molar conductivity?
Answer» Given : Concentration of solution = C = 0.02 M AgNO₃ Temperature = T = 273 + 25 = 298 K Conductivity = κ = 2.428 × 10^-3Ω^-1cm^-1 (or S cm^-1) Molar conductivity = ∧_m = ? ∧_m = \(\frac{k\times 1000}{C}\) = \(\frac{2.428\times 10^{-3}\times 1000}{0.02}\) = 121.4 Ω^-1 cm² mol^-1 (or 121.4 S cm² mol^-1) ∴ Molar conductivity = ∧_m = 121.4 Ω^-1 cm² mol^-1.

The conductivity of 0.02 M AgNO3 at 25°C is 2.428 × 10-3Ω-1cm-1. What is its molar conductivity?

Answer»

Given :

Concentration of solution = C = 0.02 M AgNO₃

Temperature = T = 273 + 25 = 298 K

Conductivity = κ = 2.428 × 10^-3Ω^-1cm^-1 (or S cm^-1)

Molar conductivity = ∧_m = ?

∧_m = \(\frac{k\times 1000}{C}\)

= \(\frac{2.428\times 10^{-3}\times 1000}{0.02}\)

= 121.4 Ω^-1 cm² mol^-1

(or 121.4 S cm² mol^-1)

∴ Molar conductivity = ∧_m

= 121.4 Ω^-1 cm² mol^-1.

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The conductivity of 0.02 M AgNO3 at 25°C is 2.428 × 10-3Ω-1cm-1. What is its molar conductivity?

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