The correct option(s) to distinguish nitrate salts of `Mn^(2+)" and Cu^(2+)` taken separately is (are)A. `Mn^(2+)` show the characteristic green colour in the flame testB. Only `Cu^(2+)` show the formation of precipitate by passing `H_(2)S` in acidic mediumC. Only `Mn^(2+)` show the formation of precipitate by passing `H_(2)S` in faintly basic mediumD. `Cu^(2+)//Cu` has higher reduction potential than `Mn^(2+)//Mn` (measured under similar conditions).

The correct option(s) to distinguish nitrate salts of `Mn^(2+)" and Cu

1.	The correct option(s) to distinguish nitrate salts of `Mn^(2+)" and Cu^(2+)` taken separately is (are)A. `Mn^(2+)` show the characteristic green colour in the flame testB. Only `Cu^(2+)` show the formation of precipitate by passing `H_(2)S` in acidic mediumC. Only `Mn^(2+)` show the formation of precipitate by passing `H_(2)S` in faintly basic mediumD. `Cu^(2+)//Cu` has higher reduction potential than `Mn^(2+)//Mn` (measured under similar conditions).
Answer» Correct Answer - B::D (b,d) Both these are correct. (b) In weakly acidic medium, only `Cu^(2+)` ions form black precipitate of CuS. (d) `E_(Cu^(2+)//Cu)^(@)(+0.34V)` is higher than that of `E_(Mn^(2+)//Mn)^(@)(-1.18V)` The other two options are not correct. (a) `Cu^(2+)" and not "Mn^(2+)` shows characteristic green colour in the flame test. (c) Both `Cu^(2+)" and "Mn^(2+)` show the formation of precipitate (CuS-Black) & MnS-Brown) by passing `H_(2)S` in faintly basic medium.