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The denominator of a fraction is one more than twice the numerator. Ifthe sum of the fraction and its reciprocal is `2(16)/(21),`find the fraction. |
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Answer» Let the numerator of the required fraction be x. Then, its denominator `=(2x+1).` `:." ""fraction "=(x)/((2x+1))" and its reciprocal "=((2x+1))/(x).` `:." "(x)/((2x+1))+((2x+1))/(x)=(58)/(21)` `implies" "21xx[x^(2)+(2x+1)^(2)]=58x(2x+1)` `implies" "21xx[5x^(2)+4x+1]=116x^(2)+58x` `implies" "11x^(2)-26x-21=0` `implies" "11x^(2)-33x+7x-21=0implies11x(x-3)+7(x-3)=0` `implies" "(x-3)(11x+7)=0impliesx-3=0" or "11x+7=0` `implies" "x=3" or "x=(-7)/(11)` `:." "x=3" "[because" numerator cannot be a negative fraction"].` `:." ""required fraction "=(x)/((2x+1))=(3)/(7).` |
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