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The diagonals of a rhombus are in the ratio 5 : 12. If its perimeter is 104 amfthe lengths of the sides and the diagonals. |
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Answer» Rombus all 4 side are equal X+x+x+x = 104 4x= 104 X= 26 cm Now diagonals of rombus bisect each other at 90 then 26² = (5x)²+(12x)² 676 = 25x² + 144x² 676 = 169x² X² = 676/169 X²= 4 X = 2 Hence 5*2 = 10 and 12*2= 24 …Hence full length of diagonals are 10+10 = 20 and 24+24=48 |
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