1.

The diagonals of a rhombus are in the ratio 5 : 12. If its perimeter is 104 amfthe lengths of the sides and the diagonals.

Answer»

Rombus all 4 side are equal

X+x+x+x = 104

4x= 104

X= 26 cm

Now diagonals of rombus bisect each other at 90 then

26² = (5x)²+(12x)²

676 = 25x² + 144x²

676 = 169x²

X² = 676/169

X²= 4

X = 2

Hence 5*2 = 10 and 12*2= 24 …Hence full length of diagonals are 10+10 = 20 and 24+24=48



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