1.

The diagram shows a CE circuit using a silicon transistor. Calculate the (a) base current (b) collector current. [VBB = 2V, VCC = 10V, RB = 100 kΩ, RL = 1 kΩ, [βdc = 200]

Answer»

Data : VBB = 2 V, 

VCC = 10 V, 

RB = 100 kΩ, 

RL = 1 kΩ,

βdc = 200.

Since it is a silicon transistor, the emitter-base barrier potential, V = 0.7 V.

The voltage across the base resistor is

VBB – VBE = 2 – 0.7 = 1.3 V

Therefore, the base current,

IB =  \(\cfrac{V_{BB}−V_{BE}}{R_B}\) = \(\cfrac{1.3}{10^5}\) = 1.3 x 10-5 = 13 μA

The collector current,

IC = βIB = 200 × 1.3 × 10-5 = 2.6 × 10-3 A = 2.6mA



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