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The diagram shows a CE circuit using a silicon transistor. Calculate the (a) base current (b) collector current. [VBB = 2V, VCC = 10V, RB = 100 kΩ, RL = 1 kΩ, [βdc = 200] |
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Answer» Data : VBB = 2 V, VCC = 10 V, RB = 100 kΩ, RL = 1 kΩ, βdc = 200. Since it is a silicon transistor, the emitter-base barrier potential, V = 0.7 V. The voltage across the base resistor is VBB – VBE = 2 – 0.7 = 1.3 V Therefore, the base current, IB = \(\cfrac{V_{BB}−V_{BE}}{R_B}\) = \(\cfrac{1.3}{10^5}\) = 1.3 x 10-5 = 13 μA The collector current, IC = βIB = 200 × 1.3 × 10-5 = 2.6 × 10-3 A = 2.6mA |
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