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The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The 24th division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is(A) 5.112 cm (B) 5.124 cm (C) 5.136 cm (D) 5.148 cm |
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Answer» Answer is (B) 5.124 cm For a given vernier callipers, 1 MSD = 5.15 - 5.10 = 0.05 cm 1 VSD = \(\frac{2.45}{50}\) = 0.049 cm ∴ L.C = 1 MSD - 1VSD = 0.001 cm Thus, the reading = 5.10 + (0.001 x 24) = 5.124 cm ⇒ diameter of cylinder = 5.124 cm |
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