The displacement-time relation for a particle can be expressed as, y = 5[cos^2 (4pit) - sin^2 (4 pi t)] . The relation shows that:

The displacement-time relation for a particle can be expressed as, y =

1.	The displacement-time relation for a particle can be expressed as, y = 5[cos^2 (4pit) - sin^2 (4 pi t)] . The relation shows that:
Answer» <html><body><p>The <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> is executing a <a href="https://interviewquestions.tuteehub.com/tag/shm-630759" style="font-weight:bold;" target="_blank" title="Click to know more about SHM">SHM</a> with amplitude 5 m <br/>The particle is executing a SHM with a frequency 4 times that of a second's pendulum <br/>The particle is executing a SHM and the velocity in its mean <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> is (<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)m/s<br/>the particle is not executing a SHM at all </p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>