InterviewSolution
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InterviewSolution
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The `E^(o)` values of the following reduction reactions are given `Fe_((aq))^(3+)+etoFe_((aq))^(2+),E^(o)=0.771V` `Fe_((aq))^(2+)to2etoFe_((s)),E^(o)=-0.447V` What will be the free energy change for the reaction `Fe_((aq))^(3+)+3e^(-)toFe_((s))" "(1F=96485C" mol"^(-1))`A. `+18.51kJ" "mol^(-1)`B. `+11.87kJ" "mol^(-1)`C. `-8.10kJ" "mol^(-1)`D. `-10.41kJ" "mol^(-1)` |
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Answer» Correct Answer - B `DeltaG^(o)=-nFE_(cell)^(o)` `Fe_((aq))^(3+)+e^(-)toFe_((aq))^(2+),DeltaG_(1)^(o)=-Fxx0.771` `Fe_((aq))^(2+)+2e^(-)toFe_((s)),DeltaG_(2)^(o)=-2xxFxx(-0.447)` `=0.894F` `Fe_((aq))^(3+)+3e^(-)toFe_((s)),DeltaG_(3)^(o)=?` `DeltaG_(3)^(o)=DeltaG_(1)^(o)+DeltaG_(2)^(o)` `DeltaG_(3)^(o)=-0.771F+0.894F` `DeltaG_(3)^(o)=0.123F=0.123xx96485` `DeltaG_(3)^(o)=11867.6J" "mol^(-1)` or `11.87kJ" "mol^(-1)`. |
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