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The `E^(@)` values for the changes given below are measured againest `NHE` at `27^(@)C`. `Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V`, `Cu^(+) + e rarr Cu, E^(@) = + 0.50 V`, `Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V` The temperature coefficient of emf a cell designed as `Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu` is `-1.4 xx 10^(-4)V` per degree. For a cell reaction in equilibrium `DeltaG = 0` and `DeltaG^(@) = -2.303 RTlog_(10)K_(c)`. The heat of reaction and entropy change during the reaction are are related by `DeltaG = DeltaH - TDeltaS`. The `E^(@)` for the reaction : `2Cu^(+) rarr Cu^(2+) + Cu` is:A. `+0.35 V `B. `-0.35 V`C. `+0.65 V`D. `-0.65 V` |
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Answer» Correct Answer - A `{:(Cu^(+)rarrCu^(2+)+e),(Cu^(+)+erarrCu):}/(2Cu^(+)rarrCu^(2+)+Cu)` `:. E^(@) = E_(OP_(Cu^(+)//Cu^(2+)))^(@)+E_(RP_(Cu^(+)//Cu))^(@)` `= -0.15 + 0.50 = +0.35 V` |
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