InterviewSolution
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InterviewSolution
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The `E^(@)` values for the changes given below are measured againest `NHE` at `27^(@)C`. `Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V`, `Cu^(+) + e rarr Cu, E^(@) = + 0.50 V`, `Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V` The temperature coefficient of emf a cell designed as `Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu` is `-1.4 xx 10^(-4)V` per degree. For a cell reaction in equilibrium `DeltaG = 0` and `DeltaG^(@) = -2.303 RTlog_(10)K_(c)`. The heat of reaction and entropy change during the reaction are are related by `DeltaG = DeltaH - TDeltaS`. The `E^(@)` for `Cu rarr Cu^(2+) + 2e` is :A. `0.325 V`B. `0.35V`C. `-0.325 V`D. `-0.35 V` |
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Answer» Correct Answer - C `{:(e+Cu^(+)rarrCu,-DeltaG^(@)=1xx0.50xxF),(e+Cu^(2+)rarrCu^(+),-DeltaG^(@)=1xx0.15xxF):}/(Cu^(2+)+2e rarrCu,-DeltaG^(@)=0.65xx1xxF=E^(@)xx2xxF)` `E^(@) = 0.325V` |
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