The electric field outside a charged long straight wire is given by `E = (1000)/(r ) V m^(-1)`, and is directed outwards. What is the sign of the charge on the wire ? If two points `A` and `B` are situated such that `r_(A) = 0.2 m` and `r_(B) = 0.4 m`, find the value of `(V_(B) - V_(A))`.

The electric field outside a charged long straight wire is given by `E

1.	The electric field outside a charged long straight wire is given by `E = (1000)/(r ) V m^(-1)`, and is directed outwards. What is the sign of the charge on the wire ? If two points `A` and `B` are situated such that `r_(A) = 0.2 m` and `r_(B) = 0.4 m`, find the value of `(V_(B) - V_(A))`.
Answer» Correct Answer - `+` charge ; `-693.1 V` As the field is directed outwards, charge on the wire must be positive `V_(B) - V_(A) = - int_(A)^(B) vec(E). Vec(dl) = - int_(r = 0.2m)^(r = 0.4m) (1000)/(r ) dr` `V_(B) - V_(A) = -1000 [log_(e) r]_(r = 0.2m)^(r = 0.4m)` `= -1000 [log_(e) 0.4 - log_(e) 0.2]` `= -1000 [log_(e) (0.4)/(0.2)]` `= -1000 log_(e) 2` `V_(B) - V_(A) = -1000xx0.6931` `= -693.1` volt

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The electric field outside a charged long straight wire is given by `E = (1000)/(r ) V m^(-1)`, and is directed outwards. What is the sign of the charge on the wire ? If two points `A` and `B` are situated such that `r_(A) = 0.2 m` and `r_(B) = 0.4 m`, find the value of `(V_(B) - V_(A))`.

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