InterviewSolution
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InterviewSolution
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The electrode with reaction `:Cr_(2)O_(7)^(2-)(aq)+14H^(o+)(aq)+6e^(-) rarr 2Cr^(3+)(aq)+7H_(2)O` can be represented asA. `Pt|H^(o+)(aq),Cr_(2)O_(7)^(2-)(aq)`B. `Pt|H^(o+)(aq),Cr_(2)O_(7)^(2-)(aq),Cr^(3+)(aq)`C. `Pt_(H2)|H^(o+)(aq),Cr_(2)O_(7)^(2-)`D. `Pt_(H2)|H^(o+)(aq),Cr_(2)O_(7)^(2-)(aq),Cr^(3+)(aq)` |
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Answer» Correct Answer - d `Cr_(2)O_(7)^(2-)` reduces to `2Cr^(3+)`, so much be represented at cathode. `H_(2)` is oxidized to `2H^(o+)`, so must be representedd at anode. So the cell representation is as shown in `(d)`. |
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