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The electronic configuration of two neutral elements A and B are `A= 1s^(2) 2s^(2) 2p^(6) 3s^(2)` `B=1s^(2) 2s^(2) 2p^(5)` Which of the following represents the structure of the compound formed by them ?A. `A ^(2+) B ^(2-)`B. `B^(2-) (A ^(-))_(2)`C. `A^(2+) (B^(-))_(2)`D. `A^(+)B^(-)` |
Answer» Correct Answer - C A loses two electrons to form `A^(2+)` while two atoms of B lose one electron each to from `2B^(-).` Therefore, the formula of the compound is `A^(2+)(B^(-))_(2).` |
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