The emf of the cell in which the following reactions, `Zn(s)+Ni^(2+) (0.1M) rarr Zn^(2+) (1.0 M) + Ni(s)` occurs, is found to 0.5105 V at 298 K. The standard emf of the cell is :A. `0.540` VB. `0.4810` VC. `0.5696 ` VD. `0.5105`V

The emf of the cell in which the following reactions, `Zn(s)+Ni^(2+) (

1.	The emf of the cell in which the following reactions, `Zn(s)+Ni^(2+) (0.1M) rarr Zn^(2+) (1.0 M) + Ni(s)` occurs, is found to 0.5105 V at 298 K. The standard emf of the cell is :A. `0.540` VB. `0.4810` VC. `0.5696 ` VD. `0.5105`V
Answer» Correct Answer - D `E_("cell") = E_("cell")^(@) + (0.0592)/(2) log _(10) ([Ni^(2+)])/([Zn^(2+)])` `0.5105 = E_("cell")^(@) + (0.0592)/(2) log (1)/(1)` or `E_("cell")^(@) = 0.5105` V

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The emf of the cell in which the following reactions, `Zn(s)+Ni^(2+) (0.1M) rarr Zn^(2+) (1.0 M) + Ni(s)` occurs, is found to 0.5105 V at 298 K. The standard emf of the cell is :A. `0.540` VB. `0.4810` VC. `0.5696 ` VD. `0.5105`V

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