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The `EMF` of the cell `:` `Pt, H_(2)(1atm)|H^(o+)(aq)||AgCl|Ag` is `0.27` and `0.26V` at `25^(@)C`, respectively. The heat of the reaction occuring inside the cell at `25^(@)C` is `………………….. kJ K^(-1)` |
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Answer» Correct Answer - `(-54.8kJ K^(-1))` `(-54.9k J K^(-1))` `((delE)/(delT))_(P)=((0.26-0.27)/(35-25))=(-0.01)/(10)V K^(-1)[n_(cell)=1]` `DeltaH=-nF[E_(cell)(at 25^(@)C)-T((delE)/(delT))_(P)]` `DeltaH=-1xx96500[0.27-298(-(0.01)/(10))]` `DeltaH=-1xx96500Cxx0.568V K^(-1)=-54812 J K^(-1)` `=-54.8 k J K^(-1)` |
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