InterviewSolution
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InterviewSolution
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The equation of a curve passing through `(2,7/2)`and havinggradient `1-1/(x^2)`at `(x , y)`is(a)`( b ) (c) y=( d ) x^(( e )2( f ))( g )+x+1( h )`(i)(b) `( j ) (k) x y=( l ) x^(( m )2( n ))( o )+x+1( p )`(q)(c)`( d ) (e) x y=x+1( f )`(g) (d) None of theseA. `y = x^(2) +x+1`B. `xy=x^(2)+x+1`C. `xy=x+1`D. None of these |
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Answer» Correct Answer - b We have, `(dy)/(dx) = 1 - 1/(x^(2))` On integrating both sides , we get ` y = x + 1/x +C` This passes through `(2,7/2)` ` :. 7/2 = 2+ 1/2 + C rArr C = 1` Thus, the equation of the curve is ` y = x + 1/x +1 or xy = x^(2) + x +1` |
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