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The equation of curve through point (1,0) which satisfies the differential equation `(1+y^(2))dx- xy ` dy = 0 , isA. `x^(2)+y^(2)=4`B. `x^(2)-y^(2)=1`C. `2x^(2)+y^(2)=2`D. None of the above |
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Answer» Correct Answer - c Given , `(dx)/(x) = (ydx)/(1+y^(2))` ` rArr log x = 1/2 log (1+y^(2))+log C rArr x = C sqrt(1+y^(2))` But it passes through (1,0) ,so we get C = 1 ` :. " Solution is " x^(2) - y^(2) = 1` |
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