The equation which can’t be solved in integers is (a) 2(x – 3) =

1.	The equation which can’t be solved in integers is (a) 2(x – 3) = 10 (b) x/3 = 5 (c) 5 – 3m = 1 (d) 2k + 1 = 1
Answer» Correct option is: (c) 5 – 3m = 1 (a) 2(x – 3) = 10 ⇒ 2x – 6 = 10 (Distributive property) ⇒ 2x – 6 + 6 = 10 + 6 (Add 6 on both sides) ⇒ 2x = 16 ⇒ 2x/2 = 16/2 (Divide by 2 on both sides) ⇒ x = 8 is an integer. (b) x/3 = 5 ⇒ x/3 × 3 = 5 × 3 (Multiply by 3 on both sides) ⇒ x = 15 is an integer. (c) 5 – 3m = 1 ⇒ 5 – 3m – 5 = 1 – 5 (Subtract 5 on both sides) ⇒ – 3m = – 4 ⇒ -3m/-3 = -4/-3 ⇒ m = 4/3 is not an integer. (d) 2k + 1 = 1 ⇒ 2k + 1 – 1 = 1 – 1 (Subtract 1 on both sides) ⇒ 2k = 0 ⇒2k/2 = 0/2 (Divide by 2 on both sides) ⇒ k = 0 is an integer So, our answer is c.

The equation which can’t be solved in integers is (a) 2(x – 3) = 10 (b) x/3 = 5 (c) 5 – 3m = 1 (d) 2k + 1 = 1

Answer»

Correct option is: (c) 5 – 3m = 1

(a) 2(x – 3) = 10 ⇒ 2x – 6 = 10 (Distributive property)

⇒ 2x – 6 + 6 = 10 + 6 (Add 6 on both sides)

⇒ 2x = 16

⇒ 2x/2 = 16/2 (Divide by 2 on both sides)

⇒ x = 8 is an integer.

(b) x/3 = 5

⇒ x/3 × 3 = 5 × 3 (Multiply by 3 on both sides)

⇒ x = 15 is an integer.

(c) 5 – 3m = 1

⇒ 5 – 3m – 5 = 1 – 5 (Subtract 5 on both sides)

⇒ – 3m = – 4

⇒ -3m/-3 = -4/-3

⇒ m = 4/3 is not an integer.

(d) 2k + 1 = 1

⇒ 2k + 1 – 1 = 1 – 1 (Subtract 1 on both sides)

⇒ 2k = 0

⇒2k/2 = 0/2 (Divide by 2 on both sides)

⇒ k = 0 is an integer

So, our answer is c.