InterviewSolution
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InterviewSolution
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The equilibrium constants for the following reactions `N_(2) (g) + 3H_(2)(g) hArr 2NH_(3) (g) N_(2) (g) + O_(2) (g) hArr 2NO(g)` `" and " H_(2)(g) +1//2 O_(2) (g) hArr H_(2)O (Ig) " are " K_(1) ,K_(2) " and " K_(3)` respectively. The equilibrium constant (K) for the reaction`2NH_(3) (g) + 2^(1)//2) O_(2) (g) hArr 2NO(g) +3H_(2) O(I) " is "`A. `K_(1)K_(2)//K_(3)`B. `K_(2)K_(3)^(3)//K_(1)`C. `K_(2)K_(3)^(2)//K_(1)`D. `K_(2)^(2)K_(3)//K_(1)` |
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Answer» Correct Answer - B Desired equilibrium equation is `2NH_(3)(g)+(5)/(2)O_(2)(g)hArr 2NO(g)+3H_(2)O(l)` It can be obtained by reversing the first equation, multiplying the third equation by 3, and adding the second equation to them: `2NH_(3)hArr N_(2)+3H_(2), 1//K_(1)` `3H_(2)+(3)/(2)O_(2)hArr 3H_(2)O, K_(3)^(3)` `(N_(2)+O_(2)hArrr 2NO, K_(2))/(2NH_(3)+(5)/(2)O_(2)hArr 2NO+3H_(2)O, K_(eq)=(K_(2)K_(3)^(3))/(K_(1)))` |
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