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The equivalent weight fo `Na_2S_2O_3` in the reaction `2Na_2S_2O_3 + I_2 rarr Na_2 S_4O_6 + 2 NaI` will be .A. `M//2`B. `M`C. `M//0.5`D. `M//8` |
Answer» Correct Answer - B `overset(+2)(S_(2))O_(3)^(2-) rarr overset(+2.5)(S_(4))O_(6)^(2-)` Sincec there are two S atoms in `S_(2)O_(3)^(2-)`, we must calculate the change in oxidation number for two S atoms only: ` 2 (+2) rarr 2 ( +2.5)` or ` +4 rarr +5` `:.` Equivalent weight `= (M)/1`. |
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