The figure shows a circular loop of radius `a` with two long parallel wires `(numbered 1 and 2)` all in the plane of the paper . The distance of each wire from the centre of the loop is `d`. The loop and the wire are carrying the same current `I`. The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at `P` due to the currents in the wires are in opposite directions. (r) There is no magnetic field at `P`. (s) The wires repel each other. (5) Consider `dgtgta`, and the loop is rotated about its diameter parallel to the wires by `30^(@)` from the position shown in the figure. If the currents in the wire are in the opposite directions, the torque on the loop at its new position will be ( assume that the net field due to the wires is constant over the loop).A. `(mu_(0)I^(2)a^(2))/d`B. `(mu_(0)I^(2)a^(2))/(2d)`C. `(sqrt3mu_(0)I^(2)a^(2))/d`D. `(sqrt3mu_(0)I^(2)a^(2))/(2d)`

The figure shows a circular loop of radius `a` with two long parallel

1.	The figure shows a circular loop of radius `a` with two long parallel wires `(numbered 1 and 2)` all in the plane of the paper . The distance of each wire from the centre of the loop is `d`. The loop and the wire are carrying the same current `I`. The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at `P` due to the currents in the wires are in opposite directions. (r) There is no magnetic field at `P`. (s) The wires repel each other. (5) Consider `dgtgta`, and the loop is rotated about its diameter parallel to the wires by `30^(@)` from the position shown in the figure. If the currents in the wire are in the opposite directions, the torque on the loop at its new position will be ( assume that the net field due to the wires is constant over the loop).A. `(mu_(0)I^(2)a^(2))/d`B. `(mu_(0)I^(2)a^(2))/(2d)`C. `(sqrt3mu_(0)I^(2)a^(2))/d`D. `(sqrt3mu_(0)I^(2)a^(2))/(2d)`
Answer» Correct Answer - B Magnetic field at mid point of two wires `=(mu_(0)l)/(pid)o x` Magnetic moment of loop `=lpia^(2)` Torque on loop `=M B sin 150^(@)` `=(mu_(0)I^(2)a^(2))/(2d)`

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