The following data were obtained during the first order thermal decomposition of `N_(2)O_(5)` (g) at constant volume : `2N_(2) O_(5)(g)to 2N_(2)O_(4)(g) +O_(2)(g)` Calculate the rate constnat.

The following data were obtained during the first order thermal decomp

1.	The following data were obtained during the first order thermal decomposition of `N_(2)O_(5)` (g) at constant volume : `2N_(2) O_(5)(g)to 2N_(2)O_(4)(g) +O_(2)(g)` Calculate the rate constnat.
Answer» Let the pressure of `N_(2)O_(5)(g)` decrease by 2x atm. As two moles of `N_(2)O_(5)` decompose to give two moles of `N_(2)O_(4)` (g) and one mole of `O_(2)(g),` the pressure of of `N_(2)O_(4)` (g) increases by 2x atm and that of `O_(2)(g)` increases by x atm. `{:(, 2N_(2)O_(5)(g),to,2N_(2) O_(4)(g)2N_(2) O_(4)(g),+, O_(2)(g)),("Start" t=0, 0.5atm,,0 atm ,,0atm),("At time t" , (0.5-2x)atm,,2xatm,,x atm):}` `P_(t) =P_(N_(2)O_(5))+P_(N_(2)O_(4))+P_(O_(2))=(0.5 -2x) +2x+x=0.5 x` `x = -0.5+x` `x=P_(t)=0.5` `P_(N_(2)O_(5))=0.5 -2x =0.5 -2 (P_(t)-0.5)=1.5 -2P_(t)` At `t=100s,P_(t)=0.512atm` `P_(N_(2)O_(5))=1.5-2xx0.152=0.476atm` Rate constant `k=(2.303)/(t)log ""(P_(i))/(P_(A))=(2.303)/(100s)log ""(0.5atm )/(0.476 atm )` `=(2.303)/(100s) xx0.0216` `4.98xx10^(-4) s^(-1)`

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The following data were obtained during the first order thermal decomposition of `N_(2)O_(5)` (g) at constant volume : `2N_(2) O_(5)(g)to 2N_(2)O_(4)(g) +O_(2)(g)` Calculate the rate constnat.

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