1.

The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied?

Answer»

LENGTH = 200 cm, diameter = 0.5 mm
length = 200 cm, diameter = 1 mmm
length = 200 cm, diameter = 2 mm
length = 200 cm, diameter = 3 m

Solution :`Y=(Fl)/(Ax)`
`Y=(Fl)/(((PID^(2))/(4))x)`
Y is same.
`thereforex=(Fl)/(((pid^(2))/(4))y)`
`thereforexprop(1)/(d^2)`
Hence the value of l must be most and that of d must be least.


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