The free energy change in related to equilibrium constant asA. `DeltaG=RT` in `k_(c)`B. `-DeltaG=RT "log" k_(c)`C. `-DeltaG=2.303 Rt "log" k_(c)`D. `-DeltaG=(RT"log"k_(c))//2.303`.

The free energy change in related to equilibrium constant asA. `DeltaG

1.	The free energy change in related to equilibrium constant asA. `DeltaG=RT` in `k_(c)`B. `-DeltaG=RT "log" k_(c)`C. `-DeltaG=2.303 Rt "log" k_(c)`D. `-DeltaG=(RT"log"k_(c))//2.303`.
Answer» Correct Answer - C `-DeltaG=2.303 Rt` log `k_(c)`

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The free energy change in related to equilibrium constant asA. `DeltaG=RT` in `k_(c)`B. `-DeltaG=RT "log" k_(c)`C. `-DeltaG=2.303 Rt "log" k_(c)`D. `-DeltaG=(RT"log"k_(c))//2.303`.

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