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The gravitational field in a region is given by vec(E) = (2hat(i) + 3hat(j))N//Kg. The workdone by the field when the particle is moved on the line 3y + 2x = 5 |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`vec(E) = 2hat(i) + 3 hat(j)` <br/> The field is represented as <br/> Slope `m_(1) = Tan theta_(1) = 3//2` <br/> The line `<a href="https://interviewquestions.tuteehub.com/tag/3y-311505" style="font-weight:bold;" target="_blank" title="Click to know more about 3Y">3Y</a> + <a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a> = 5` can be represented as <br/> slope `m_(2) = Tan theta_(2) = -2//3` <br/> `m_(1) xx m_(2) = -1` <br/> Since, the direction of the field and <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> are <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> the workdone by the field on the particle is zero. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_SLV_035_S01.png" width="80%"/></body></html> | |