The gravitationl potential due to a mass distribution isV = (A)/(sqrt(x^(2) + a^(2))), then the gravitational. Field is.

The gravitationl potential due to a mass distribution isV = (A)/(sqrt(

1.	The gravitationl potential due to a mass distribution isV = (A)/(sqrt(x^(2) + a^(2))), then the gravitational. Field is.
Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/ay-386628" style="font-weight:bold;" target="_blank" title="Click to know more about AY">AY</a>)/((<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(2) + a^(2))^(1//2))`in the x-direction <br/>`(Ax)/((x^(2) + a^(2))^(3//2))` inx-direction <br/>`A(x^(2) + a^(2))` in y-direction <br/>2xA in z-direction </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>