1.

The gravitationl potential due to a mass distribution isV = (A)/(sqrt(x^(2) + a^(2))), then the gravitational. Field is.

Answer»

`(AY)/((X^(2) + a^(2))^(1//2))`in the x-direction
`(Ax)/((x^(2) + a^(2))^(3//2))` inx-direction
`A(x^(2) + a^(2))` in y-direction
2xA in z-direction

Answer :B


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