1.

The half life period of a first order reaction is 60 min. What percentage will be left after 240 min.A. 0.175B. 0.15C. 0.125D. 0.1

Answer» Correct Answer - c
`n = (45)/(15) = 3` = No. of half lives
`N = N_(0) ((1)/(2))^(n) = 100 xx ((1)/(2))^(3) = 12.5%`


Discussion

No Comment Found

Related InterviewSolutions