InterviewSolution
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InterviewSolution
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The half-life period of `U^(234)` is `2.5 xx 10^(5)` years. In how much time is the quantity of the isotope reduce to 25% of the original amount? |
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Answer» Initial amount of this isotope `N_(0) = 100` Final amount of the isotope N = 25 We know that, `N = ((1)/(2))^(n) N_(0)` So, `25 = ((1)/(2))^(n) xx 100` or `(25)/(100) = ((1)/(2))^(n)` or `(1)/(4) = ((1)/(2))^(n)` or `((1)/(2))^(2) = ((1)/(2))^(n)` or n = 2 Time taken `T = n xx t_(1//2)` `= 2 xx 2.5 xx 10^(5) = 5 xx 10^(5)` years |
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