The height of a parallelogram is one-third of its base. If the area of

1.	The height of a parallelogram is one-third of its base. If the area of the parallelogram is 108 cm2, find its base and height.
Answer» Let us assume the base of the parallelogram be x cm. and height of the parallelogram will be (1/3)x cm. From the question it is given that the area of the parallelogram is 108 cm². ∴Area of the parallelogram = base × height = 108 = (x) × ((1/3)x) = 108 = (1/3)x² = x² = (108 × 3) = x² = 324 = x = √324 = x = 18 Then, The base of the parallelogram be x is 18 cm Height of the parallelogram will be (1/3)x = (1/3) × 18 = 6 cm

The height of a parallelogram is one-third of its base. If the area of the parallelogram is 108 cm2, find its base and height.

Answer»

Let us assume the base of the parallelogram be x cm.

and height of the parallelogram will be (1/3)x cm.

From the question it is given that the area of the parallelogram is 108 cm².

∴Area of the parallelogram = base × height

= 108 = (x) × ((1/3)x)

= 108 = (1/3)x²

= x² = (108 × 3)

= x² = 324

= x = √324

= x = 18

Then,

The base of the parallelogram be x is 18 cm

Height of the parallelogram will be (1/3)x = (1/3) × 18 = 6 cm