The horizontal distance x and the vertical height y of a projectile at time t are given by x = a tandy = bt^(2)+ct wherea, b and c are constants. Then

The horizontal distance x and the vertical height y of a projectile at

1.	The horizontal distance x and the vertical height y of a projectile at time t are given by x = a tandy = bt^(2)+ct wherea, b and c are constants. Then
Answer» <html><body><p>The speed of the projectile 1 second after it is fired is `(a^(2)+b^(2)+<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^(2))^(1//2)`<br/>The angle with the horizontal at which the projectile is fired is `tan^(-1)(c//a)`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> due to gravity is `-<a href="https://interviewquestions.tuteehub.com/tag/2b-300274" style="font-weight:bold;" target="_blank" title="Click to know more about 2B">2B</a>`<br/>The <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> speed of the projectile is `(a^(2)+c^(2))^(1//2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B::C::D</body></html>