The horse power needed to pump 1000 kg of water in a tank in 5 minutes under pressure of 100 g wt/(mm)^(2) is appromiately equalt o x (1 hp =746 Watt). Find the value of x.

The horse power needed to pump 1000 kg of water in a tank in 5 minutes

1.	The horse power needed to pump 1000 kg of water in a tank in 5 minutes under pressure of 100 g wt/(mm)^(2) is appromiately equalt o x (1 hp =746 Watt). Find the value of x.
Answer» Solution :`m=1000 kg` `t=5"min"=5 xx 60=300s` `P=100"g WT (mm)"^(2)` `=(100)/(1000) xx (9.8)/((10^(-3))^(2)) m^(2)` `=(9.8 xx 10^6)/(10)` `=9.8 xx 10^(6))/(10)` `=9.8 xx 10^(5) N//m^(2)` `P=W/t=(PV)/(t)` `=(9.8 xx 10^(5) xx "MASS")/(300 xx "density")` `=(9.8 xx 10^(5) xx 1000)/(300 xx 1000)` `=4.37 hp approx 4`