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The horse power needed to pump 1000 kg of water in a tank in 5 minutes under pressure of 100 g wt/(mm)^(2) is appromiately equalt o x (1 hp =746 Watt). Find the value of x.

Answer» <html><body><p></p>Solution :`m=1000 kg` <br/> `t=<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>"min"=5 xx 60=300s` <br/> `P=100"g <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> (mm)"^(2)` <br/> `=(100)/(1000) xx (9.8)/((10^(-3))^(2)) m^(2)` <br/> `=(9.8 xx 10^<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(10)` <br/> `=9.8 xx 10^(6))/(10)` <br/> `=9.8 xx 10^(5) N//m^(2)` <br/> `P=W/t=(PV)/(t)` <br/> `=(9.8 xx 10^(5) xx "<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/(300 xx "density")` <br/> `=(9.8 xx 10^(5) xx 1000)/(300 xx 1000)` <br/> `=4.37 hp approx 4`</body></html>


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