The initial state of a certain gas is (P_(i)V_(i) T_(i)). It undergoes expansion till its volume becomes V_(int).Consider the following two cases. a) The expansion takes place at constant temperature. b) The expansion takes place at constant pressure. Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more ?

The initial state of a certain gas is (P_(i)V_(i) T_(i)). It undergoes

1.	The initial state of a certain gas is (P_(i)V_(i) T_(i)). It undergoes expansion till its volume becomes V_(int).Consider the following two cases. a) The expansion takes place at constant temperature. b) The expansion takes place at constant pressure. Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more ?
Answer» <html><body><p></p>Solution :The P-V <a href="https://interviewquestions.tuteehub.com/tag/diagram-950736" style="font-weight:bold;" target="_blank" title="Click to know more about DIAGRAM">DIAGRAM</a> for each case is <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in the <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a>. In case (i) `P_(i)V_(i)=P_(f)V_(f)` : therefore <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> is isothermal. Work done = area under the PV curve so work is more when the gas expands at constant pressure.<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_C_C13_SLV_046_S01.png" width="80%"/></body></html>