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The input resistance of a silicon transistor is `665Omega`. Its base current is changed by `15 muA` which result in the change in collector current by `2mA`. This transistor is used as a common emitter amplifier with a load resistance of 5kOmega calculate current gain, `beta_(a.c.)`, transconductance `g_(m)` and voltage gain `A_(v)` of the amplifier. |
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Answer» Here, `R_(i)=665Omega, R_(0)=5kOmega=5xx10^(3)Omega` `beta_(ac)=(DeltaI_c)/(DeltaI_b)=(2mA)/(15muA)=(2xx10^(-3)A)/(15xx10^(-6)A)=133.3` `R_(i)=(DeltaV_(BE))/(DeltaI_b) or Delta V_(BE)=R_(i)xxDeltaI_b=665xx15xx10^(-6)V` `g_(m)=(DeltaI_c)/(DeltaV_(BE))=(2xx10^(-3))/(665xx15xx10^(-6))=0.2Omega_(-1)` `A_(V)=beta_(a.c.)xxR_(0)/R_(i)=133.3xx(5xx10^(3))/665=10^(3)` |
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