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The ions from among the following which are colourless are `:` `(i)Ti^(+4)" "(ii)Cu^(+1)" "(iii)Co^(+3)" "(iv)Fe^(+2)`A. (i) and (ii) onlyB. (i),(ii) and (iii)C. (iii) and (iv)D. (ii) and (iii). |
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Answer» Correct Answer - A (i) Valence shell electron configuration of `Ti^(4+)` is `3d^(10)4s^(0)`. As theere is no unpaired electrons for d-d transition, the solution of ions will be colourless. (ii) Valence shell electron configuration of `Cu^(+)` is `3d^(10)4s^(0)`. As all electrons are paired, there is no d-d transiton, so the solution of ions will be colourless. (iii) Valence shell electron configuraiton of `Co^(3+)` is `3d^(6)4s^(0)`. As there are 4 unpaired electrons, there is d-d transition of electron, so the solution of ions will be coloured. (iv) Valence shell electron configuration of `Fe^(2+)` is `3d^(6)4s^(0)`. As there are 4 unpaired electrons, there is d-d transition of electron, so the solution of ions will be coloured. |
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